Thread Rating:
  • 0 Vote(s) - 0 Average
  • 1
  • 2
  • 3
  • 4
  • 5

Wind sensor
#1

Hi,

I have one anemometer and one windvane Vector Instruments.

The anemometer is an A100K which I do think will give 25 pulses per revolution or 10Hz per British Knots.
Would it be possible to use this sensor? 

I have seen in the software that it's possible to adapt the settings for the anemometer but the settings for the other sensors will only give a few pulses per revolution. what are the limmits?
 

The windvane is an W200P wich has an 1Kohm potentiometer with an 3° dead-band, it will give you 0° - 357°.
I do belive that this windvane should be possible to use?

All my other sensors should be compatible with this very nice project, the only questionmarks are for my wind sensors.

I do hope that I'll find some answers here soon. Smile
Reply
#2

Hi, the Didcot vane settings might be a starting point,  I have the same wind vane though not used as yet, I am using Didcot sensors at the moment. I have a vector A100R anemometer fitted with a reed switch, which works fine. Not sure if a conversion to reed switch is an easy change.

http://www.windspeed.co.uk/ws/index.php?...e&SubMenu=

The vane will work fine. Similar to didcot.

http://www.meteocercal.info/forum/Thread...nemometers

Download the Didcot pdf , for specification.
Reply
#3

(24-02-2017, 16:22)miraclebox Wrote:  Hi,

I have one anemometer and one windvane Vector Instruments.

The anemometer is an A100K which I do think will give 25 pulses per revolution or 10Hz per British Knots.
Would it be possible to use this sensor? 

I have seen in the software that it's possible to adapt the settings for the anemometer but the settings for the other sensors will only give a few pulses per revolution. what are the limmits?

Hi,

Really nice instruments!
The problem to use the A100K anemometer with the WeatherDuino Pro2 system is not the number of pulses it produces, but its output voltage.
The A100K model needs a power supply between 10v to 30V, no problem with this (you can use the 12V pin), however its output voltage is <0.1V than power supply voltage approx. and you can't apply a voltage greater than 5V to an Arduino input pin.

There are ways to lower the amplitude of a square wave signal, and limit it to 5V. Google for it, or perhaps someone here can post a circuit to do it. A simple voltage divider using resistors, may not be appropriate.

As an additional info, the Vector Instruments models A100L2, A100LK, A100LM and A100R/K should work without any additional circuitry (not yet added to the list of supported instruments, because I don't have any for testing).


(24-02-2017, 16:22)miraclebox Wrote:  The windvane is an W200P wich has an 1Kohm potentiometer with an 3° dead-band, it will give you 0° - 357°.
I do belive that this windvane should be possible to use?

It should work.

Reply




Users browsing this thread: 1 Guest(s)