20-11-2017, 10:56
Hi,
Thanks for your kind words. Re-reading my text, the second sentence in my third paragraph is not strictly correct and perhaps I should really have said:
"So 3.5 revs/sec would give 1.445 metres of equivalent linear movement of the centre of each cup. With the known Wind Run of 5.0 metres per second, the Anemometer Factor would be (5.0 / 1.445) = 3.46."
Cheers, Alan.
PS: Sometime I must look to see exactly how the Wind Pulses are counted. At a "maximum" windpeed of 100 mph (160 km/hr) this particular anemometer would deliver 560 Hz (or pulses per second). That's not too high for most "electronic" (hardware) counters, but the 2 ms repetition period might be an issue for some interrupt-driven software.
Thanks for your kind words. Re-reading my text, the second sentence in my third paragraph is not strictly correct and perhaps I should really have said:
"So 3.5 revs/sec would give 1.445 metres of equivalent linear movement of the centre of each cup. With the known Wind Run of 5.0 metres per second, the Anemometer Factor would be (5.0 / 1.445) = 3.46."
Cheers, Alan.
PS: Sometime I must look to see exactly how the Wind Pulses are counted. At a "maximum" windpeed of 100 mph (160 km/hr) this particular anemometer would deliver 560 Hz (or pulses per second). That's not too high for most "electronic" (hardware) counters, but the 2 ms repetition period might be an issue for some interrupt-driven software.