It is not really a question of Weatherduino matching your gauge. if your gauge is in error then it is in error.
However one of the many useful attributes of weatherduino is that it is very configurable, and you can compensate for the gauge error, in the case of the rain gauge, almost infinitely, although the arithmetic becomes a bit harder.
You mention 653ml of water registered 18.2mm on the readout. The other figure you will need is how many tips it took to achieve this. If you are going to alter Weatherduino to compensate for Gauge error then you will need these three figures:
Readout figure: 18.2mm
Water introduced to gauge: 653ml
Number of tips to achieve the readout:??
If you have change the TX config file to 0.200 as follows;
*/
#define COLLECTOR_TYPE 0.200 // Please note: Values must be in metric units. Max. resolution: 3 decimal digits
// --------------------------------------------------------------------------------------
then it will have tipped 91 times to register 18.2mm. (18.2mm @ 0.200mm per tip = 91 tips.)
This would work out 7.18ml per bucket tip. (653 / 91 = 7.18)
As your gauge is 200 mm diam then:
i) 200 / 2 = 100
ii) 100 x 100 x π = 31428.6 mm2 cross sectional area.
Therefore: we have 31428mm2 area receiving 653ml of water this does equate to 20.78 mm of rain:
(653 / 31.4286 = 20.78 )
20.78 divided by 91 = 0.229 mm of rain represented on readout for each tip:
Therefore you need to change your TX config file to 0.229; as follows. (Don’t put in 2.2 as in your last post you will register 10 times the correct rainfall)
*/
#define COLLECTOR_TYPE 0.229 // Please note: Values must be in metric units. Max. resolution: 3 decimal digits
// --------------------------------------------------------------------------------------
Then as a check;
Get 628ml of water for our 200mm diameter OTA gauge (not 653ml for our 203.89 diam TB3) and introduce into gauge as described previously. You should get 100 tips and 20ml registering on the readout. (314ml should tip 50 times and register 10mm on readout).
628ml / bucket size 7.18 = 87.465 tips
87.465 x 0.229 = 20.03 mm which is as much accuracy as we can achieve with three decimal places available.
However one of the many useful attributes of weatherduino is that it is very configurable, and you can compensate for the gauge error, in the case of the rain gauge, almost infinitely, although the arithmetic becomes a bit harder.
You mention 653ml of water registered 18.2mm on the readout. The other figure you will need is how many tips it took to achieve this. If you are going to alter Weatherduino to compensate for Gauge error then you will need these three figures:
Readout figure: 18.2mm
Water introduced to gauge: 653ml
Number of tips to achieve the readout:??
If you have change the TX config file to 0.200 as follows;
*/
#define COLLECTOR_TYPE 0.200 // Please note: Values must be in metric units. Max. resolution: 3 decimal digits
// --------------------------------------------------------------------------------------
then it will have tipped 91 times to register 18.2mm. (18.2mm @ 0.200mm per tip = 91 tips.)
This would work out 7.18ml per bucket tip. (653 / 91 = 7.18)
As your gauge is 200 mm diam then:
i) 200 / 2 = 100
ii) 100 x 100 x π = 31428.6 mm2 cross sectional area.
Therefore: we have 31428mm2 area receiving 653ml of water this does equate to 20.78 mm of rain:
(653 / 31.4286 = 20.78 )
20.78 divided by 91 = 0.229 mm of rain represented on readout for each tip:
Therefore you need to change your TX config file to 0.229; as follows. (Don’t put in 2.2 as in your last post you will register 10 times the correct rainfall)
*/
#define COLLECTOR_TYPE 0.229 // Please note: Values must be in metric units. Max. resolution: 3 decimal digits
// --------------------------------------------------------------------------------------
Then as a check;
Get 628ml of water for our 200mm diameter OTA gauge (not 653ml for our 203.89 diam TB3) and introduce into gauge as described previously. You should get 100 tips and 20ml registering on the readout. (314ml should tip 50 times and register 10mm on readout).
628ml / bucket size 7.18 = 87.465 tips
87.465 x 0.229 = 20.03 mm which is as much accuracy as we can achieve with three decimal places available.